2x^2+3x+7=2x

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Solution for 2x^2+3x+7=2x equation: 



2x^2+3x+7=2x

We move all terms to the left:

2x^2+3x+7-(2x)=0

We add all the numbers together, and all the variables

2x^2+x+7=0

a = 2; b = 1; c = +7;
Δ = b2-4ac
Δ = 12-4·2·7
Δ = -55
Delta is less than zero, so there is no solution for the equation

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